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Question

Physics Question on Gauss Law

A cone of base radius R and height h is located in a uniform electric field E\overrightarrow{E} parallel to its base. The electric flux entering the cone is :

A

12\frac{1}{2} E h R

B

E h R

C

2 E h R

D

4 E h R

Answer

E h R

Explanation

Solution

flux ϕ=EA\phi = E\cdot A_{\bot}
=E(12h×2R)= E\left(\frac{1}{2}h\times2R\right)
=Ehr= Ehr