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Question: A cone made of insulating material has a total charge Q spread uniformly over its sloping surface. ...

A cone made of insulating material has a total charge Q spread uniformly over its sloping surface.

Calculate the energy required to take a test charge q from infinity to apex A of cone. The slant length is L. कुचालक पदार्थ से बने एक शंकु पर कुल आवेश Q इसकी ढालनुमा सतह पर एकसमान रूप से फैला हुआ है। एक परीक्षण आवेश q को अनन्त से शंकु के शीर्ष A तक लाने में आवश्यक ऊर्जा की गणना कीजिए। ढाल की लम्बाई L है।

Answer

\frac{Qq}{2\pi \epsilon_0 L}

Explanation

Solution

  1. The energy required to move a test charge qq from infinity to point AA is qVAqV_A, where VAV_A is the electric potential at point AA.

  2. The potential at AA due to the uniformly charged sloping surface is calculated by integrating the potential contributions from infinitesimal charge elements over the surface.

  3. A suitable element of charge is a ring of charge on the sloping surface at a slant distance ll' from the apex.

  4. The potential due to this ring at the apex is calculated using dV=14πϵ0dQldV = \frac{1}{4\pi\epsilon_0} \frac{dQ}{l'}, where dQ=σdAdQ = \sigma dA and dA=2πrdldA = 2\pi r' dl' is the area of the ring.

  5. The radius of the ring rr' is related to the slant distance ll' by r=(R/L)lr' = (R/L)l'.

  6. Integrating dVdV from l=0l'=0 to l=Ll'=L gives the total potential VAV_A.

  7. Expressing the result in terms of the total charge Q=σπRLQ = \sigma \pi R L gives VA=Q2πLϵ0V_A = \frac{Q}{2\pi L \epsilon_0}.

  8. The required energy is W=qVA=Qq2πϵ0LW = qV_A = \frac{Qq}{2\pi \epsilon_0 L}.

Answer: Qq2πϵ0L\frac{Qq}{2\pi \epsilon_0 L}