Question

A conductor with rectangular cross-section has dimensions

(a × 2a × 4a) as shown in figure Resistance across AB is x, across CD is y and across EF is z. Then –

• A. x = y = z
• B. x > y > z
• C. y > z > x
• D. x > z > y

Answer 1

Answer: (D)

x > z > y

Answer 2

$\frac{\rho(4a)}{a \times 2a}$ = $\frac{2\rho}{a}$

y = $\frac{\rho(a)}{2a \times 4a}$ = $\frac{\rho}{8a}$

z = $\frac{\rho(2a)}{a \times 4a}$ = $\frac{\rho}{2a}$

\ x > z > y