Question
Question: A conductor of resistance 20 Ω is cut into n equal parts. All the parts are bundled together in para...
A conductor of resistance 20 Ω is cut into n equal parts. All the parts are bundled together in parallel. The equivalent is obtain as 51Ω. The number of parts is –
A
n = 2
B
n = 4
C
n = 8
D
n = 10
Answer
n = 10
Explanation
Solution
when wire is cut into 'n' parts then resistance of each part becomes r = R/n
When they are connected in parallel Req = nr
Req = nr = n2R ; 51 =n220 ; ∴ n2= 100 ⇒ n = 10 parts