Question

A conductor of 3 m in length is moving perpendicularly to magnetic field of $10^{- 3}$tesla with the speed of $10^{2}m/s$, then the e.m.f. produced across the ends of conductor will be

• A. 0.03 volt
• B. 0.3 volt
• C. $3 \times 10^{- 3}volt$
• D. 3 volt

Answer 1

Answer: (B)

0.3 volt

Answer 2

$e = Bvl = 3 \times 10^{- 3} \times 10^{2} = 0.3\mspace{6mu} volt$