Question

A conductor gets a charge of 50 μC when it is connected to a battery of e.m.f. 5 V. Calculate capacitance of the conductor.

Answer 1

10 μF

Answer 2

The capacitance of a conductor is defined as the ratio of the charge stored on it to the potential difference across it.

Given:

• Charge acquired by the conductor, $Q = 50 \, \mu C = 50 \times 10^{-6} \, C$
• Electromotive force (e.m.f.) of the battery, $V = 5 \, V$

Formula: The capacitance $C$ is given by the formula:

$$C = \frac{Q}{V}$$

Calculation: Substitute the given values into the formula:

$$C = \frac{50 \times 10^{-6} \, C}{5 \, V}$$ $$C = 10 \times 10^{-6} \, F$$ $$C = 10 \, \mu F$$

The capacitance of the conductor is $10 \, \mu F$.