Question
Question: A conductor ABOCD moves along its bisector with a velocity of 1 m/s through a perpendicular magnetic...
A conductor ABOCD moves along its bisector with a velocity of 1 m/s through a perpendicular magnetic field of 1 wb/m2, as shown in fig. If all the four sides are of 1m length each, then the induced emf between points A and D is
A
0
B
1.41 volt
C
0.71 volt
D
None of the above
Answer
1.41 volt
Explanation
Solution
There is no induced emf in the part AB and CD because they are moving along their length while emf induces between B and C i.e. between A and D can be calculated as follows
Induced emf between B and C = Induced emf between A and B = 
