Question
Question: A conductor ab of arbitrary shape carries current \[I\]flowing from b to a. The length vector \[\ove...
A conductor ab of arbitrary shape carries current Iflowing from b to a. The length vector abis oriented from a to b. The force F experienced by the conductor in a uniform magnetic field B is.
(A) F=−I(ab×B)
(B) F=I(B×ab)
(C) F=−I(ba×B)
(D) All of these
Solution
We should know the formula for force on a current-carrying wire.
We should know the identity of(A×B)=−(B×A).We should know the reversal of a vector ab=−ba.
Complete step by step answer:
A magnetic field is a vector quantity that describes the magnetic influence on moving electric charges, electric currents, and magnetized materials. A charge that is moving in a magnetic field experiences a force normal to its velocity and the magnetic field. Lorentzforce, the force exerted on a charged particle q moving with velocity v through an electric field E and magnetic field B. The entire electromagnetic force F on the charged particle is called the Lorentz force (after the Dutch physicist Hendrik A. Lorentz) and is given by
F=qE+(qv×B)
Let us consider a wire of length ab, and a current is passing from b to a.
Then force experienced on the wire is,
We know that,
dF=I(dl×B)
By integrating this we can find the value of F.
∫dF=b∫aI(dl×B)
∫dF=Ib∫a(dl×B)
F=I(ba×B)- - - - - - - - - - - - - - - - - - (1)
So Option (C) is correct.
We know that ab=−ba . - - - - - - - - - - - - - - - - - - (2)
By rearranging (1) using (2)
We get,
F=I(ba×B)=−I(ab×B)- - - - - - - - - - - - - - - - - - (3)
Hence Option (A) is correct.
Again we know that (A×B)=−(B×A)- - - - - - - - - - - - - - - - - - (4)
By rearranging (3) using (4),
we get,
So,