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Question: A conductor ab of arbitrary shape carries current \[I\]flowing from b to a. The length vector \[\ove...

A conductor ab of arbitrary shape carries current IIflowing from b to a. The length vector ab\overrightarrow {ab} is oriented from a to b. The force F\overrightarrow F experienced by the conductor in a uniform magnetic field B\overrightarrow B is.
(A) F=I(ab×B)\overrightarrow F = - I(\overrightarrow {ab} \times B)
(B) F=I(B×ab)\overrightarrow F = I(B \times \overrightarrow {ab} )
(C) F=I(ba×B)\overrightarrow F = - I(\overrightarrow {ba} \times B)
(D) All of these

Explanation

Solution

We should know the formula for force on a current-carrying wire.
We should know the identity of(A×B)=(B×A)(A \times B) = - (B \times A).We should know the reversal of a vector ab=ba\overrightarrow {ab} = - \overrightarrow {ba} .

Complete step by step answer:
A magnetic field is a vector quantity that describes the magnetic influence on moving electric charges, electric currents, and magnetized materials. A charge that is moving in a magnetic field experiences a force normal to its velocity and the magnetic field. Lorentzforce, the force exerted on a charged particle q moving with velocity v through an electric field E and magnetic field B. The entire electromagnetic force F on the charged particle is called the Lorentz force (after the Dutch physicist Hendrik A. Lorentz) and is given by
F  =  qE  +  (qv  ×  B)F\; = \;qE\; + \;\left( {qv\; \times \;B} \right)
Let us consider a wire of length ab, and a current is passing from b to a.
Then force experienced on the wire is,

We know that,
dF=I(dl×B)dF = I(dl \times B)
By integrating this we can find the value of F.
dF=baI(dl×B)\int {dF} = \int\limits_b^a {I(dl \times B)}
dF=Iba(dl×B)\int {dF} = I\int\limits_b^a {(dl \times B)}
F=I(ba×B)F = I(ba \times B)- - - - - - - - - - - - - - - - - - (1)
So Option (C) is correct.
We know that ab=ba\overrightarrow {ab} = - \overrightarrow {ba} . - - - - - - - - - - - - - - - - - - (2)
By rearranging (1) using (2)
We get,
F=I(ba×B)=I(ab×B)F = I(ba \times B) = - I(ab \times B)- - - - - - - - - - - - - - - - - - (3)
Hence Option (A) is correct.
Again we know that (A×B)=(B×A)(A \times B) = - (B \times A)- - - - - - - - - - - - - - - - - - (4)
By rearranging (3) using (4),
we get,
So,

F = - I(ab \times B) \\\ = - I( - B \times ab) \\\ = I(B \times ab) \\\ \end{gathered} $$ Since options (A), (B), (C) are correct, hence the correct Option is (D) **Note:** You should be aware of vector identities.If any two options are correct, then no need to find the other one since there is an option of all are correct. ( you can save time) You should also be aware and careful about sign conversion.