Question

A conductivity cell has two platinum electrodes of $1.2cm^{2}$ area, separated by a distance of 0.8 cm. The cell constant is,

• A. $0.66cm^{- 1}$
• B. $1.5cm^{- 1}$
• C. $0.96cm^{- 1}$
• D. $0.66cm$

Answer 1

Answer: (A)

$0.66cm^{- 1}$

Answer 2

Cell constant $= \frac{l}{a} = \frac{0.8}{1.2} = 0.66cm^{- 1}.$