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Question: A conducting wire of cross-sectional area 1 *cm*<sup>2</sup> has 3 × 10<sup>23</sup>*m*<sup>–3</sup>...

A conducting wire of cross-sectional area 1 cm2 has 3 × 1023m–3 charge carriers. If wire carries a current of 24 mA, the drift speed of the carrier is

A

5 × 10–6m/s

B

5 × 10–3m/s

C

0.5 m/s

D

5 × 10–2m/s

Answer

5 × 10–3m/s

Explanation

Solution

vd=ineA=24×10−33×1023×1.6×10−19×10−4=5×10−3 m/sv _ { d } = \frac { i } { n e A } = \frac { 24 \times 10 ^ { - 3 } } { 3 \times 10 ^ { 23 } \times 1.6 \times 10 ^ { - 19 } \times 10 ^ { - 4 } } = 5 \times 10 ^ { - 3 } \mathrm {~m} / \mathrm { s }