Question

A conducting sphere of radius R is charged to a potential of V volt. Then the electric field at a distance r (> R) from the centre of the sphere would be –

• A. $\frac{RV}{r^{2}}$
• B. $\frac{V}{r}$
• C. $\frac{rV}{R^{2}}$
• D. $\frac{R^{2}V}{r^{3}}$

Answer 1

Answer: (A)

$\frac{RV}{r^{2}}$

Answer 2

V = Ž Q =

E_P = $\frac { \mathrm { kQ } } { \mathrm { r } ^ { 2 } }$ = $\frac { \mathrm { VR } } { \mathrm { r } ^ { 2 } }$