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Question: A conducting sphere A having a radius a is charged to a potential V<sub>1</sub>. Now it is surrounde...

A conducting sphere A having a radius a is charged to a potential V1. Now it is surrounded by another conducting spherical shell of radius b. The potential V2 acquired by the sphere A after it is connected to shell B by a thin conducting wire is-

A

V1ab\frac{a}{b}

B

V1ba\frac{b}{a}

C

V1(a+b)b\frac{V_{1}(a + b)}{b}

D

V1aa+b\frac{V_{1}a}{a + b}

Answer

V1ab\frac{a}{b}

Explanation

Solution

V1 = Kqa\frac { \mathrm { Kq } } { \mathrm { a } }

V2 = Kqb\frac { \mathrm { Kq } ^ { \prime } } { \mathrm { b } } = Kqb\frac { \mathrm { Kq } } { \mathrm { b } }

= =