Solveeit Logo

Question

Question: A conducting rod AC of length 4l is rotated about a point O in a uniform magnetic field \(\overright...

A conducting rod AC of length 4l is rotated about a point O in a uniform magnetic field B\overrightarrow{B}direction into the paper AO=l and OC=3l. Then

A. VAVO=Bωl22{{V}_{A}}-{{V}_{O}}=\dfrac{B\omega {{l}^{2}}}{2}
B. VOVC=72Bωl2{{V}_{O}}-{{V}_{C}}=\dfrac{7}{2}B\omega {{l}^{2}}
C. VAVC=4Bωl2{{V}_{A}}-{{V}_{C}}=4B\omega {{l}^{2}}
D. VCVO=92Bωl2{{V}_{C}}-{{V}_{O}}=\dfrac{9}{2}B\omega {{l}^{2}}

Explanation

Solution

When a conducting rod is placed in a magnetic field B then it experiences a certain force. The rotating rod will contain some amount of emf. Thus, the potential difference between two points can be calculated.

Complete answer:
The potential difference between point O and A is VOVA{{V}_{O}}-{{V}_{A}}.
The potential difference between point O and C is VOVC{{V}_{O}}-{{V}_{C}}.
Thus, the potential difference between A and C is,
VAVC=(VOVA)(VOVC).......(i){{V}_{A}}-{{V}_{C}}=({{V}_{O}}-{{V}_{A}})-({{V}_{O}}-{{V}_{C}}).......(i)
For a rotating rod, the electromotive force (emf) is given as,
e=BVl2e=\dfrac{BVl}{2}
Since, the angular velocity (ω)(\omega ) is
ω=V/l\omega =V/l
Rewriting the equations, we get,
e=Bωl22e=\dfrac{B\omega {{l}^{2}}}{2}
Thus, to calculate total emf for the length, we write,
de=Bωl.dlde=B\omega l.dl
For the potential difference between A and O,
VOVA=0lBωl.dl VOVA=Bωl22 \begin{aligned} & {{V}_{O}}-{{V}_{A}}=\int\limits_{0}^{l}{B\omega l.dl} \\\ & {{V}_{O}}-{{V}_{A}}=\dfrac{B\omega {{l}^{2}}}{2} \\\ \end{aligned}
For the potential difference between O and C,
VOVC=03lBωl.dl VOVC=9Bωl22 \begin{aligned} & {{V}_{O}}-{{V}_{C}}=\int\limits_{0}^{3l}{B\omega l.dl} \\\ & {{V}_{O}}-{{V}_{C}}=\dfrac{9B\omega {{l}^{2}}}{2} \\\ \end{aligned}
Thus, the potential difference between the point A and C from equation (i),

& {{V}_{A}}-{{V}_{C}}=\dfrac{9B\omega {{l}^{2}}}{2}-\dfrac{B\omega {{l}^{2}}}{2} \\\ & {{V}_{A}}-{{V}_{C}}=4B\omega {{l}^{2}} \\\ \end{aligned}$$ **Hence, the option C is correct.** **Note:** The potential difference depends on the length of the conducting rod. When a conducting rod is placed in a magnetic field then the direction of the flow of electrons and the direction of magnetic field turns to rod producing a torque which results in an electromotive force.