Question

A conducting rod AB of length l = 1m is moving at a velocity n = 4 m/s making an angle of 30° with its length. A uniform magnetic field B = 2T exist in a direction perpendicular to the plane of motion, then –

• A. n_A –n_B = 8 n
• B. n_A –n_B = 4 n
• C. n_B –n_A = 8 n
• D. n_B –n_A = 4 n

Answer 1

Answer: (B)

n_A –n_B = 4 n

Answer 2

e = B (n sin 30°) l = 4 volt

fleming right hand I_ind B to A

Ž V_A – V_B = 4 volt