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Question

Physics Question on Faradays laws of induction

A conducting loop in the shape of a right angled isosceles triangle of height 10cm10\, cm is kept such that the 9090^{\circ} vertex is very close to an infinity long conducting wire (see the figure). The wire is electrically insulated from the loop. The hypotenuse of the triangle is parallel to the wire. The current in the triangular loop is in counterclockwise direction and increased at a constant rate of 10As110 \,As ^{-1}. Which of the following statement (s) is (are) true?

A

There is a repulsive force between the wire and the loop,

B

If the loop is rotated at a constant angular speed about the wire, an additional emf of (μ0π)\left(\frac{\mu_{0}}{\pi}\right) volt is induced in the wire

C

The magnitude of induced emf in the wire is (μ0π)\left(\frac{\mu_{0}}{\pi}\right) volt

D

The induced current in the wire is in opposite direction to the current along the hypotenuse

Answer

The magnitude of induced emf in the wire is (μ0π)\left(\frac{\mu_{0}}{\pi}\right) volt

Explanation

Solution

Here didt=10A/S\frac{ di }{ dt }=10 A / S
for mutual inductance
dϕ=μ02πir(2rdr)d \phi=\frac{\mu_{0}}{2 \pi} \frac{ i }{ r }(2 r dr )
ϕ=μ0πi04dr\phi=\frac{\mu_{0}}{\pi} i \int\limits_{0}^{4} dr
ϕ=(μ0πd)i=Mi\phi=\left(\frac{\mu_{0}}{\pi} d \right) i = Mi
M=μ0πd=0.1μ0πM =\frac{\mu_{0}}{\pi} d =0.1 \frac{\mu_{0}}{\pi}
When current through loop increases then magnetic flux
ϕ=Mi\phi= Mi
ε=dϕdt\varepsilon=\frac{d \phi}{ dt }
ε=Mdidt=μ0π×10×0.1\varepsilon= M \frac{ di }{ dt }=\frac{\mu_{0}}{\pi} \times 10 \times 0.1
ε=μ0π\varepsilon=\frac{\mu_{0}}{\pi}
Force between loop and conductor is repulsive.