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Question

Physics Question on Faradays laws of induction

A conducting circular loop is placed in a uniform magnetic field, B=0.025TB = 0.025\, T with its plane perpendicular to the loop. The radius of the loop is made to shrink at a constant rate of 1mms11 \,mm \,s^{-1}. The induced emf when the radius is 2cm2 \,cm, is

A

2πμV2\pi \, \mu V

B

πμV\pi \,\mu V

C

π2μV\frac{\pi}{2}\,\mu V

D

2μV2\, \mu V

Answer

πμV\pi \,\mu V

Explanation

Solution

Here, Magnetic field, B=0.025TB=0.025\,T Radius of the loop, r=2cm=2×102mr=2\, cm=2\times10^{-2}\, m Constant rate at which radius of the loop shrinks, drdt=1×103ms1\frac{d r}{d t}=1\times10^{-3}\,m\,s^{-1} Magnetic flux linked with the loop is ϕ=BAcosθ=B(πr2)cos0=Bπr2\phi=BA\, cos\theta =B \left(\pi r^{2}\right)cos0^{\circ}=B\pi r^{2} The magnitude of the induced emf is ε=dϕdt=ddt(Bπr2)=Bπ2rdrdt\left|\varepsilon\right|=\frac{d \phi}{d t}=\frac{d}{d t}\left(B\pi r^{2}\right)=B\pi2r \frac{dr}{d t} =0.025×π×2×2×102×1×103=0.025\times\pi\times2\times2\times10^{-2}\times1\times10^{-3} =π×106V=πμV=\pi\times10^{-6}\, V =\pi\,\mu V