Question
Physics Question on Faradays laws of induction
A conducting circular loop is placed in a uniform magnetic field, B=0.025T with its plane perpendicular to the loop. The radius of the loop is made to shrink at a constant rate of 1mms−1. The induced emf when the radius is 2cm, is
A
2πμV
B
πμV
C
2πμV
D
2μV
Answer
πμV
Explanation
Solution
Here, Magnetic field, B=0.025T Radius of the loop, r=2cm=2×10−2m Constant rate at which radius of the loop shrinks, dtdr=1×10−3ms−1 Magnetic flux linked with the loop is ϕ=BAcosθ=B(πr2)cos0∘=Bπr2 The magnitude of the induced emf is ∣ε∣=dtdϕ=dtd(Bπr2)=Bπ2rdtdr =0.025×π×2×2×10−2×1×10−3 =π×10−6V=πμV