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Question

Physics Question on Electromagnetic induction

A conducting circular loop is placed in a uniform magnetic field 0.04T0.04\, T with its plane perpendicular to the magnetic field. The radius of the loop starts shrinking at 2mm/s.2\, mm/s. The induced emf in the loop when the radius is 2cm2\, cm is

A

4.8πμV4.8\pi\mu V

B

0.8πμV0.8\pi\mu V

C

1.6πμV1.6\pi\mu V

D

3.2πμV3.2\pi\mu V

Answer

3.2πμV3.2\pi\mu V

Explanation

Solution

e=dϕdt=ddt(Bπr2)e =\frac{ d \phi}{ dt }=\frac{ d }{ dt }\left( B \pi r ^{2}\right)
=2πrBdrdt=2 \pi rB \frac{ dr }{ dt }
=2×π×2×102×4×102×2×103=2 \times \pi \times 2 \times 10^{-2} \times 4 \times 10^{-2} \times 2 \times 10^{-3}
=3.2×106πVol=3.2πμV=3.2 \times 10^{-6} \pi Vol =3.2\, \pi \mu V