Question
Question: A conductance cell when filled with \[{{0}}{{.5 M KC}}l\] solution (specific conductance \( = 6.67 \...
A conductance cell when filled with 0.5MKCl solution (specific conductance =6.67×10−3Ω−1cm−1 ) registers a resistance of 243Ω . Its cell constant is:
A. 1.62cm
B. 1.62cm−1
C. 1.62dm−1
D. 1.62m−1
Solution
First from the formula of resistance R=ρl/a we will find the relation between cell constant and conductivity (or specific conductance). Then using that relation we can find the cell constant value.
Formula used:
R=ρl/a where, R is resistance, ρ is resistivity, l is length and a is area of the cell.
Also, l/a is the cell constant
K=G×l/a where, K is the conductivity, G is conductance.
Complete step by step answer:
First let us find the relation between cell constant and conductivity (or specific conductance):
We know that R=ρl/a
And l/a = cell constant
Therefore we can also write it as l/a = R/ρ
We also are aware that 1/ρ=G , i.e., reciprocal of resistivity is conductivity.
Therefore we have the final relation l/a=R×G
Now let’s see the given values, we have
G =6.67×10−3Ω−1cm−1
R = 243Ω
Now we put the values in the final relation that we derived to get the value of cell constant
l/a=6.67×10−3Ω−1cm−1×243Ω
Upon doing the calculations we have the answer as l/a=1.62cm−1 .
Therefore the correct option is Option B.
Additional Information:
Cell constant is the ratio of the distance between the cell electrodes to the area (cross-sectional) that the electrodes occupy. It is usually measured for a cell containing a solution whose conductivity is already known to us. Because of this reason we use KCl solution since its conductivity can be known to accurately measure at various concentrations and temperatures.
Note:
For a particular cell the value of l/a is constant. This value is generally written on the cell and can be experimentally determined too. Cell constant is actually a multiplier constant which when multiplied with the measured current gives the electrical conductivity of the solution.