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Question: A condenser of capacitance 10 mF has been charged to 100 V. It is now connected to another uncharged...

A condenser of capacitance 10 mF has been charged to 100 V. It is now connected to another uncharged condenser in parallel. The common potential becomes 40 V. The capacitance of another condenser is –

A

15 mF

B

5 mF

C

10 mF

D

16 mF

Answer

15 mF

Explanation

Solution

C1 = 10mF C2 = ?

V1 = 100 V V2 = 0

Vcommon = 40 V

Vcommon =