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Question

Question: A concave lens of glass, refractive index 1.5, has both surfaces of same radius of curvature R. On i...

A concave lens of glass, refractive index 1.5, has both surfaces of same radius of curvature R. On immersion in a medium of refractive index 1.75, it will behave as a-

A

Convergent lens of focal length 3.5 R

B

Convergent lens of focal length 3.0 R

C

Divergent lens of focal length 3.5 R

D

Divergent lens of focal length 3.0 R

Answer

Convergent lens of focal length 3.5 R

Explanation

Solution

1f=(1.51.751)(1R1R)\frac { 1 } { \mathrm { f } } = \left( \frac { 1.5 } { 1.75 } - 1 \right) \left( \frac { 1 } { - \mathrm { R } } - \frac { 1 } { \mathrm { R } } \right)

f = = + 3.5R, converging