Question

A compound X with seven carbon atoms on treatment with Br₂ and KOH gives Y. Y gives carbylamine test and upon diazotisation and coupling with phenol gives azodye. X is

• A. C₆H₅CONH₂
• B. CH­₃ – (CH₂)₅ – CONH₂
• C. CH₃ – $\overset{\begin{aligned} & CH_{3} \\ & | \end{aligned}}{\underset{\begin{aligned} & | \\ & CH_{3} \end{aligned}}{C -}}$CH_­2 – CH₂ – CONH₂
• D. O – CH₃ – C₆H₄NH₂

Answer 1

Answer: (A)

C₆H₅CONH₂

Answer 2

Since Y gives coupling reaction after diazotisation it suggest that Y can be aniline or benzener ring substituted aniline. Since Y has been obtained from Hoffmann bromamide it means has – CO NH₂ group with benzene ring. Hence it is C₆H₅CONH₂