Solveeit Logo
Login

Question

Question: A compound (X) with molecular formula \(C_{3}H_{9}N\) reacts with l\(C_{6}H_{5}SO_{2}Cl\) to give a ...

A compound (X) with molecular formula C3H9NC_{3}H_{9}N reacts with lC6H5SO2ClC_{6}H_{5}SO_{2}Cl to give a solid which is insoluble in alkali.(X) is

A

CH3CH2CH2NH2CH_{3}CH_{2}CH_{2}NH_{2}

B

CH3−N∣∣CH3:CH3CH_{3} - \overset{CH_{3}}{\underset{CH_{3}}{\underset{|}{\overset{|}{N}}}:}

C

CH3−NH−CH2CH3CH_{3} - NH - CH_{2}CH_{3}

D

CH3−CH∣CH3−NH2CH_{3} - \underset{CH_{3}}{\underset{|}{CH}} - NH_{2}

Answer

CH3−NH−CH2CH3CH_{3} - NH - CH_{2}CH_{3}

Explanation

Solution

: Since the compound reacts with bezenesulphonyl chloride to give a product which is insoluble in alkali, it shows there is no H attached to N in the product hence the compound X is a secondary amine.

}{ \underset{N - Ethyl - N - Methylbenzenesulphonamide}{CH_{3} - \underset{C_{2}H_{5}}{\underset{|}{N}} - SO_{2}C_{6}H_{5}}}$$