Question

A compound (X) having molecular formula $\mathrm { C } _ { 4 } \mathrm { H } _ { 8 } \mathrm { O } _ { 2 }$ is hydrolysed by water in presence of an acid to give a carboxylic acid (Y) and an alcohol (Z). (Z) on oxidation with chromic acid gives (Y), (X), (Y) and (Z) are.

X Y Z

• A. $\mathrm { CH } _ { 3 } \mathrm { COOCH } _ { 3 }$ $\mathrm { CH } _ { 3 } \mathrm { COOH }$ $\mathrm { CH } _ { 3 } \mathrm { OH }$
• B. $\mathrm { CH } _ { 3 } \mathrm { COOC } _ { 2 } \mathrm { H } _ { 5 }$ $\mathrm { CH } _ { 3 } \mathrm { COOH }$ $\mathrm { C } _ { 2 } \mathrm { H } _ { 5 } \mathrm { OH }$
• C. $\mathrm { C } _ { 2 } \mathrm { H } _ { 5 } \mathrm { COOH }$ $\mathrm { C } _ { 2 } \mathrm { H } _ { 5 } \mathrm { OH }$
• D. $\mathrm { CH } _ { 3 } \mathrm { COOC } _ { 2 } \mathrm { H } _ { 5 }$ $\mathrm { C } _ { 2 } \mathrm { H } _ { 5 } \mathrm { COOH }$ $\mathrm { CH } _ { 3 } \mathrm { OH }$

Answer 1

Answer: (B)

$\mathrm { CH } _ { 3 } \mathrm { COOC } _ { 2 } \mathrm { H } _ { 5 }$ $\mathrm { CH } _ { 3 } \mathrm { COOH }$ $\mathrm { C } _ { 2 } \mathrm { H } _ { 5 } \mathrm { OH }$

Answer 2

: