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Question: A compound \({M_p}{X_q}\) has cubic-close packing (c.c.p) arrangement of X. Its unit-cell structure ...

A compound MpXq{M_p}{X_q} has cubic-close packing (c.c.p) arrangement of X. Its unit-cell structure is shown below. The empirical formula of the compound is:

A) MXMX
B) MX2M{X_2}
C) M2X{M_2}X
D) M5X14{M_5}{X_{14}}

Explanation

Solution

Count the number of M atoms and X atoms at different positions in the given structure of the unit-cell. To answer this question, you should know the contribution of an atom per unit cell, when the atoms are located at the corners, face-centre, and the edge-centre.

Complete step by step answer:
Given structure of the unit cell of the compound MpXq{M_p}{X_q}:

Now, let us understand the positions of X atoms:
Number of X atoms located at the corners = 8,
Number of X atoms located at the face-centres = 6
And, contribution of an atom located at the corner in a unit cell = 18\dfrac{1}{8} per unit cell.
Contribution of an atom located at the face-centre in a unit cell = 12\dfrac{1}{2} per unit cell.
Thus, total number of X atoms in the unit cell = 8 corner atoms ×18 atom per unit cell + 6 face - centred atoms × 12 atom per unit cell {\text{8 corner atoms }} \times \dfrac{1}{8}{\text{ atom per unit cell + 6 face - centred atoms }} \times {\text{ }}\dfrac{1}{2}{\text{ atom per unit cell }}
\therefore Total number of X atoms = 1+3=4 atoms1 + 3 = 4{\text{ atoms}}

Now, there are four M atoms located at the edge-centres and one atom is located at the body centre of the unit cell.
Contribution of an atom located at the edge centre in a unit-cell = 14\dfrac{1}{4} per unit cell.
Contribution of an atom located at the body-centre in a unit-cell = 1 per unit cell.
Thus, total number of M atoms in the unit cell = 4 edge - centred atoms × 14 atom per unit cell + 1 body - centred atom × 1 atom per unit cell{\text{4 edge - centred atoms }} \times {\text{ }}\dfrac{1}{4}{\text{ atom per unit cell + 1 body - centred atom }} \times {\text{ 1 atom per unit cell}}
\therefore Total number of M atoms = 1+1=2 atoms1 + 1 = 2{\text{ atoms}}
So, there are a total two M atoms and four X atoms in the given unit cell structure. Thus, the empirical formula of the compound is M2X4{M_2}{X_4} or on simplifying, MX2M{X_2}.
So, the correct answer is “Option B”.

Note: Cubic close packed (ccp) unit cell or face-centred cubic (fcc) unit cell are the same unit cells but two different names. A face-centred unit cell contains atoms at all the corners and at the centre of all the faces of the cubic unit cell. A key point to note is that each atom located at the face centre is shared between two adjacent unit cells and hence only 12\dfrac{1}{2} of each atom belongs to the unit cell.