Question

A compound is formed by cation C and anion A. The anions form hexagonal close packed (hcp) lattice and the cations occupy 75% of octahedral voids. The formula of the compound is :

• A. $C_2A_3$
• B. $C_3A_2$
• C. $C_3A_4$
• D. $C_4A_3$

Answer 1

Answer: (C)

$C_3A_4$

Answer 2

The correct option is (C) :$C_3A_4$