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Question

Chemistry Question on Some basic concepts of chemistry

A compound has C=40%,H=13.33%C =40 \%, H =13.33 \% and N=46.67%.N =46.67 \% . The empirical formula is:

A

CH4NCH_{4}N

B

C2H5NC_{2}H_{5}N

C

CH2NCH_{2}N

D

CH4N2CH_{4}N_{2}

Answer

CH4NCH_{4}N

Explanation

Solution

Consider the compound to be made of 100g100 g. Convert percentile to weight in grams. then, convert wt. in grams to moles. Moles of C=40/12=3.33C=40 / 12=3.33 Moles of H=13.33/1=13.33H =13.33 / 1=13.33 Moles of N=46.6/14=3.33N =46.6 / 14=3.33 Now divide each mole value by lowest value of nn as: C=3.33/3.33=1 H=13.33/3.33=4.00 N=3.33/3.33=1\begin{array}{l} C =3.33 / 3.33=1 \\\ H =13.33 / 3.33=4.00 \\\ N =3.33 / 3.33=1 \end{array} The emperical formula is CH4NCH _{4} N.