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Question: A compound contains atoms of three elements A, B and C. If the oxidation number of A is \( + 2\), B ...

A compound contains atoms of three elements A, B and C. If the oxidation number of A is +2 + 2, B is +5 + 5 and that of C is −2 - 2, the possible formula of the compound is
A.A3(BC4)2{A_3}{(B{C_4})_2}
B.A3(BC)2{A_3}{(BC)_2}
C.ABC2AB{C_2}
D.A2(BC3)2{A_2}{(B{C_3})_2}

Explanation

Solution

We have to know that the oxidation number or likewise called the oxidation state is the quantity of electrons that an iota either loses or gains to shape a synthetic bond. It assumes a vital part fit as a fiddle, calculation and classification of a compound. A compound is consistently impartial.

Complete answer:
We realize that the oxidation number of a compound is the quantity of electrons acquired or lost to frame synthetic bonds with different iotas; it is the level of oxidation of a molecule. Some significant focuses to recollect are that, oxidation number of a free component is zero. The oxidation number of hydrogen is +1 + 1however it is taken as - 1 in the event that it responds with a less electronegative component.
The oxidation number of oxygen is −2 - 2 yet it is taken as −1 - 1as far as peroxides. Likewise various gatherings of the intermittent table have their oxidation number contingent upon their electron action.
Oxidation numbers may be positive, negative or zero. In this request we see that there are three parts A, B and C given to us with oxidation states as +2 + 2, +5 + 5 and −2 - 2.
We realize that the overall recipe of the compound with these three components will be AxByCz{A_x}{B_y}{C_z} where, X, Y, Z are the atomicity of the iota. In this way, we realize that a compound is consistently nonpartisan thus the oxidation number of the compound will be zero.
2x+5y−2z=02x + 5y - 2z = 0
The greatest oxidation state can't surpass +8 + 8 or −3 - 3 since that will be the most extreme electron acquire and lose from the orbital, so we utilize hit and preliminary strategy and we find that (x,y,z)(x,y,z) can be taken as either (1,2,6)(1,2,6) or (3,2,8)(3,2,8) as per the arrangement of the condition framed. Thus, the recipe of the compound can be composed as
A(BC3)2A{(B{C_3})_2}or A3B2C8{A_3}{B_2}{C_8} .

The correct answer is (A).

Note:
We have to know that the highest oxidation state of nonmetals is equal to the total number of electrons present in its valence shell and add a plus sign to it as it indicates the available electrons. The sum of the oxidation states of all the atoms in an ion is taken equal to the charge on the ion.