Question
Question: A compound contains 38.8% C, 16.0% H and 45.2% N. The empirical formula of the compound would be: ...
A compound contains 38.8% C, 16.0% H and 45.2% N. The empirical formula of the compound would be:
A.CH3NH2
B.CH3CN
C.C2H5CN
D.CH2(NH)2
Solution
The empirical formula for a compound is defined as the ratio of the numbers of atoms of different elements that are combined in order to form the molecule of the compound. For example, if we have element X, Y and Z then their formula will be their ratio X:Y:Z.
Complete step by step answer:
Mass of Nitrogen = 45.2 g
Mass of Carbon = 38.8 g
Mass of Hydrogen = 16 g
In order to find the empirical formula of the compound, the moles of each element has to be calculated;
The formula used for empirical formula calculation is;
Moles of atom =molar mass of atom mass of atom............(1)
Substituting the given values in equation 1;
For carbon;
Moles of carbon =molar mass of carbon mass of carbon
Moles of carbon =12g/mole 38.8g
Moles of carbon =3.23moles
For hydrogen;
Moles of hydrogen =1g/mole 16g
Moles of hydrogen =1moles
For nitrogen;
Moles of Nitrogen =14g/mole 45.2g
Moles of Nitrogen =3.23moles
Now, the next step will be to divide the moles calculated for each element with the smallest mole value i.e. 3.32.
Thus for carbon element;
Ratio will be = 3.233.23=1
For nitrogen, the ratio will be= 3.233.23=1
For hydrogen, the ratio will be = 3.2316=5
According to the calculations, the ratio is for carbon, hydrogen and nitrogen is= 1:5:1
Thus the formula of the compound isCH5N.
So, the correct answer is “Option A”.
Note:
Mass of an atom is due to the weight of neutrons and protons in its nucleus, the weight is the same for both but one is charged and the other is neutral.
Mole is defined as the exactly equal to 6.02214076×1023particles in an element, and is the unit of measurement for the amount of a substance present.