Question

A compound A has a molecular formula $C_{2}Cl_{3}OH.$ It reduces Fehling solution and on oxidation gives a monocarboxylic acid (2). A is obtained by action of chlorine on ethyl alcohol. A is.

• A. Chloral
• B. $CHCl_{3}$
• C. $CH_{3}Cl$
• D. Chloroacetic acid

Answer 1

Answer: (A)

Chloral

Answer 2

$\underset{A}{C_{2}Cl_{3}OH} + \text{Fehlingsol.} \rightarrow \underset{\text{Red}\mspace{6mu}\text{ppt}}{Cu_{2}O}$

It means –CHO group is present.

$\underset{A}{C_{2}Cl_{3}OH}\overset{\quad\text{Oxidation}\quad}{\rightarrow}\underset{\text{Monocarboxylicacid}}{CCl_{3} - COOH}$

It means only one –CHO group is present.

$C_{2}H_{5}OH + Cl_{2} \rightarrow CH_{3}CHO + 2HCl$

$CH_{3}CHO + 3Cl_{2} \rightarrow \underset{\text{Chloral}}{CCl_{3}CHO} + 3HCl$