Question

A composite slab consists of two slabs A and B of different materials but of the same thickness placed one on top of the other. The thermal conductivities of A and B are k₁ and k₂ respectively. A steady temperature difference of 12⁰C is maintained across the composite slab. If k₁ =k₂/2, the temperature difference across slab A will be :

• A. 4⁰C
• B. 8⁰C
• C. 12⁰
• D. 16⁰

Answer 1

Answer: (B)

8⁰C

Answer 2

R = $\frac{L}{KA}$

$\frac{R_{1}}{R_{2}}$ = $\frac{L_{1}}{L_{2}}$× $\frac{K_{2}}{K_{1}}$ × $\frac{A_{2}}{A_{1}}$