Question

A company dissolves $‘X’$ amount of $CO_2$ at $298\ K$ in $1$ litre of water to prepare soda water. $X$ = _____ $× 10^{–3}$ g. (nearest integer)
(Given: partial pressure of $CO_2$ at $298\ K = 0.835$ bar. Henry’s law constant for $CO_2$ at $298\ K = 1.67$ Kbar. Atomic mass of $H$, $C$ and $O$ is $1$, $12$, and $6$ g mol–1, respectively)

Answer 1

$P_g = (K_H) X_g$
Where, $X_g$ is mole fraction of gas in solution
$0.835 = 1.67 × 103 (X_{CO_2})$
$(X_{CO_2}) = 5×10^{-4}$
Mass of $CO_2$ in 1 L water = $1221×10^{–3} g$
So, the answer is $1221$.