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Question

Quantitative Aptitude Question on Permutations and Combinations

A committee is to be formed from amongst 9 boys and 6 girls. In how many ways can the boys and girls divide themselves into groups of three so that no group has more than 2 girls and no group has all boys?

A

15(9!)15 (9!)

B

20(9!)20 (9!)

C

45(8!)45 (8!)

D

452(9!)\frac{45}{2} (9!)

E

452(8!)\frac{45}{2} (8!)

Answer

452(9!)\frac{45}{2} (9!)

Explanation

Solution

The correct answer is option (D): 452(9!)\frac{45}{2} (9!)