Question

A collimated beam of monochromatic g-rays of intensity I₀ penetrates a material and the intensity I varies with depth x according to the relationship I = $I_{0}e^{–\mu x}$. Given that a is the distance which causes the intensity to be halved. Then-

• A. m = 1/a
• B. m = (ln 2)/a
• C. m = 2/a
• D. m = 1/2a

Answer 1

Answer: (B)

m = (ln 2)/a

Answer 2

X= $\frac{\ln 2}{\mu} \Rightarrow \mu = \frac{\ln 2}{x} = \frac{\ln 2}{a}$