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Question: A coin is tossed three times in succession. If E is the event that there are at least two heads and ...

A coin is tossed three times in succession. If E is the event that there are at least two heads and F is the event in which fast throw is a head, then =

A

¾

B

3/8

C

½

D

1/8

Answer

¾

Explanation

Solution

S = {HHH,HHT, HTH, THH, HTT, THT, TTH,TTT

n(5) = 4, n(F) = 4 and n(E∩F) = 3.

∴ P (EF)=P(EF)P(F)=3/84/8=34\left( \frac { E } { F } \right) = \frac { P ( E \cap F ) } { P ( F ) } = \frac { 3 / 8 } { 4 / 8 } = \frac { 3 } { 4 }