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Question: A coin is tossed three times in succession. If *E* is the event that there are at least two heads an...

A coin is tossed three times in succession. If E is the event that there are at least two heads and F is the event in which first throw is a head, then P(EF)=P \left( \frac { E } { F } \right) =

A

34\frac { 3 } { 4 }

B

38\frac { 3 } { 8 }

C

12\frac { 1 } { 2 }

D

18\frac { 1 } { 8 }

Answer

34\frac { 3 } { 4 }

Explanation

Solution

S={HHH,HHT,HTH,THH,HTT,THT,TTH,TTT}S = \{ H H H , H H T , H T H , T H H , H T T , T H T , T T H , T T T \}

n(EF)=3n ( E \cap F ) = 3

P(EF)=P(EF)P(F)=3/84/8=34P \left( \frac { E } { F } \right) = \frac { P ( E \cap F ) } { P ( F ) } = \frac { 3 / 8 } { 4 / 8 } = \frac { 3 } { 4 }.