Question

A coin is dropped in a lift. It takes time $t_{1}$ to reach the floor when lift is stationary. It takes time $t_{2}$ when lift is moving up with constant acceleration. Then

• A. $t_{1} > t_{2}$
• B. $t_{2} > t_{1}$
• C. $t_{1} = t_{2}$
• D. $t_{1} > > t_{2}$

Answer 1

Answer: (A)

$t_{1} > t_{2}$

Answer 2

For stationary lift $t_{1} = \sqrt{\frac{2h}{g}}$and when the lift is moving up with constant acceleration