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Question: A coil of wire of a certain radius \((r)\) has \[600\] turns and a self- inductance of \[108mH\] . T...

A coil of wire of a certain radius (r)(r) has 600600 turns and a self- inductance of 108mH108mH . The self- inductance of coil with same radius and 500500 turns will is:
A. 80mH80mH
B. 75mH75mH
C. 108mH108mH
D. 90mH90mH

Explanation

Solution

To answer this question, we must first understand self-inductance in general before moving on to the query that is solely based on it. The property of a current-carrying coil that resists or opposes the change in current flowing through it is known as self-inductance. This is primarily owing to the self-induced e.m.f. generated by the coil.

Complete answer:
We know that a solenoid's or coil's self-inductance is determined by,
L=μ0N2AlL = \dfrac{{{\mu _0}{N^2}A}}{l}
Where LL is the solenoid's self-inductance, is the medium's permeability, AA is the cross-sectional area, NN is the number of turns, and ll is the solenoid's or coil's length.
The self -inductance of a coil is clearly proportional to the square of the number of turns.
Therefore,
L1L2=(n1n2)2\dfrac{{{L_1}}}{{{L_2}}} = {\left( {\dfrac{{{n_1}}}{{{n_2}}}} \right)^2}
So, now we will put all the given values in the above equation and find the unknown.
108mHL2=60025002\Rightarrow \dfrac{{108mH}}{{{L_2}}} = \dfrac{{{{600}^2}}}{{{{500}^2}}}
Now proceeding into the equation, we will cross multiply and evaluate for L2{L_2}
L2=108×50026002 L2=108×2536  \Rightarrow {L_2} = 108 \times \dfrac{{{{500}^2}}}{{{{600}^2}}} \\\ \Rightarrow {L_2} = 108 \times \dfrac{{25}}{{36}} \\\
L2=75mH\therefore {L_2} = 75mH
Therefore, the self- inductance of coil with same radius and 500500 turns will be 75mH75mH

Hence, the correct option is: (B) 75mH75mH

Additional information:
The attribute of self-induction of a coil is that it tends to retain the magnetic flux associated with it and opposes any change in the flux by generating current in it. A coil's inertia is equivalent to mechanical inertia. Self-induction is known as the inertia of electricity for this reason.

Note:
Mutual inductance should not be confused with self-inductance. Mutual inductance involves two or more inductors, whereas the former uses a single coil or inductor. Mutual inductance is when an inductor's magnetic flux is connected into another inductor.