Question
Physics Question on Electromagnetic induction
A coil of wire having finite inductance and resistance has a conducting ring placed coaxially within it. The coil is connected a battery at time t = 0 , so that a time dependent current I1(t) starts flowing through the coil. If I2(t) is the current induced in the ring and B (t) is the magnetic field at the axis of the coil dut to I1(t) then as a function of time (t > 0), the product I2(t)B(t)
increases with time
decreases with time
does not vary with time
passes through a maximum
passes through a maximum
Solution
The equation of I1(t),I2(t) and B(t) will take the following forms I1(t)=K1(1−e−k2t)→ current growth in L - R circuit B(t)=K3(1−e−k2t)→B(t)∝I1(t) I2(t)=K4e−k2t [I2(t)=Re2ande2∝=−MdtdI1] Therefore, the product I2(t)B(t)=K5e−k2t(1−e−k2t) The value of this product zero at t=0 and t=0 . Therefore, the product will pass throiigh a maximum value.