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Question

Physics Question on Electromagnetic induction

A coil of wire having finite inductance and resistance has a conducting ring placed coaxially within it. The coil is connected a battery at time t = 0 , so that a time dependent current I1(t)I_1(t) starts flowing through the coil. If I2(t)I_2(t) is the current induced in the ring and B (t) is the magnetic field at the axis of the coil dut to I1(t)I_1(t) then as a function of time (t > 0), the product I2(t)B(t)I_2(t) \,B(t)

A

increases with time

B

decreases with time

C

does not vary with time

D

passes through a maximum

Answer

passes through a maximum

Explanation

Solution

The equation of I1(t),I2(t)I_1 (t) , I_2 (t) and B(t)B(t) will take the following forms I1(t)=K1(1ek2t)I_1 (t) = K_1 (1 - e^{-k \, 2t} ) \rightarrow current growth in L - R circuit B(t)=K3(1ek2t)B(t)I1(t)B(t) = K_3 (1 - e^{-k \, 2t} ) \rightarrow B(t) \propto I_1 (t) I2(t)=K4ek2tI_2 (t) = K_4e^{-k\, 2t} [I2(t)=e2Rande2=MdI1dt]\left[ I_2 (t) = \frac{e_2}{R} \, and \, e_2 \, \propto = - M \frac{dI_1}{dt}\right] Therefore, the product I2(t)B(t)=K5ek2t(1ek2t)I_2 (t) B (t) = K_5 e^{-k \, 2t} ( 1 - e^{-k \, 2t}) The value of this product zero at t=0t = 0 and t=0t = 0 . Therefore, the product will pass throiigh a maximum value.