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Question

Question: A coil of resistance 300 ohm and self inductance 1.5 henry is connected to an ac source of frequency...

A coil of resistance 300 ohm and self inductance 1.5 henry is connected to an ac source of frequency The phase difference between voltage and current is

A

B

3030 ^ { \circ }

C

4545 ^ { \circ }

D

6060 ^ { \circ }

Answer

4545 ^ { \circ }

Explanation

Solution

By using tanϕ=XLR=2πvLR\tan \phi = \frac { X _ { L } } { R } = \frac { 2 \pi v L } { R }

tanϕ=2π×100π×1.5300=1\tan \phi = \frac { 2 \pi \times \frac { 100 } { \pi } \times 1.5 } { 300 } = 1 ⇒ φ = 45o.