Question
Physics Question on Alternating current
A coil of resistance 10Ω and inductance 5H is connected to a 100V battery. Then the energy stored in the coil is
A
250J
B
250erg
C
125J
D
125erg
Answer
250J
Explanation
Solution
Final current, I=RE
I=10A
Energy stored in the magnetic field
U=21Li
21×5×(10)2=250J