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Question

Question: A coil of resistance 10 Ω and an inductance 5H is connected to a 100 volt battery. Then energy store...

A coil of resistance 10 Ω and an inductance 5H is connected to a 100 volt battery. Then energy stored in the coil is

A

125 erg

B

125 J

C

250 erg

D

250 J

Answer

250 J

Explanation

Solution

U=12Li2U=12×5×(10010)2=250JU = \frac{1}{2}Li^{2} \Rightarrow U = \frac{1}{2} \times 5 \times \left( \frac{100}{10} \right)^{2} = 250J