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Question: A coil of one loop is made from a wire of length L and there after a coil of two loops is made from ...

A coil of one loop is made from a wire of length L and there after a coil of two loops is made from same wire, then the ratio of magnetic field at the centre of coils will be
A. 1:4
B. 1:1
C. 1:8
D. 4:1

Explanation

Solution

Place the values in the formula for length of wire by taking two different radii into consideration and on equating them we find the answer.
A magnetic field is a vector field that describes the magnetic influence on an electric charge of other moving charges or magnetised materials.

Complete step by step solution:
Write all the values which are provided,
Length of the wire is L
Now we can let the radius of first and second loop be R1R_1​ and R2R_2​ respectively,
Then,
According to the question,
L=2πR1L = 2\pi {R_1}(for the first loop)
And,
L=2×2πR2L = 2 \times 2\pi {R_2}(second loop)

Now equating we get,
2πR1=2×2πR22\pi {R_1} = 2 \times 2\pi {R_2}
Bringing R1{R_1}and R2{R_2}in one side we get,
R2R1=2π2×2π\dfrac{{{R_2}}}{{{R_1}}} = \dfrac{{2\pi }}{{2 \times 2\pi }}
By further solving we get,
R2R1=12\dfrac{{{R_2}}}{{{R_1}}} = \dfrac{1}{2}
Now we know that magnetic field at the centre of the coil of radius R is given by,
B=μ0nI2RB = \dfrac{{{\mu _0}nI}}{{2R}}
Now for the first and second loop the magnetic field at the centre of the coil of radius R1{R_1}and R2{R_2}is
B1{B_1}=μ0n1I2R1\dfrac{{{\mu _0}{n_1}I}}{{2{R_1}}}
And,
B2{B_2}=μ0n2I2R2\dfrac{{{\mu _0}{n_2}I}}{{2{R_2}}}

Now,
B1B2=μ0n1I2R1μ0n2I2R2\dfrac{{{B_1}}}{{{B_2}}} = \dfrac{{\dfrac{{{\mu _0}{n_1}I}}{{2{R_1}}}}}{{\dfrac{{{\mu _0}{n_2}I}}{{2{R_2}}}}}
Now cancelling out μ0{\mu _0}, 2 and I we get,
B1B2=n1R2n2R1\dfrac{{{B_1}}}{{{B_2}}} = \dfrac{{{n_1}{R_2}}}{{{n_2}{R_1}}}
Now we know the values of n1={n_1} = 1, n2={n_2} = 2 and R2R1=12\dfrac{{{R_2}}}{{{R_1}}} = \dfrac{1}{2}
Putting the values in the above equation we get,
B1B2=12×12\dfrac{{{B_1}}}{{{B_2}}} = \dfrac{1}{2} \times \dfrac{1}{2}
Which is equal to
B1B2=14\dfrac{{{B_1}}}{{{B_2}}} = \dfrac{1}{4}
It can be also written as,
B1:B2=1:4{B_1}:{B_2} = 1:4

Therefore, the correct option is A.

Note: Students must remember that the radius of the two will not be same that is why we have two different radii i.e. R1 and R2.