Question
Question: A coil of one loop is made from a wire of length L and there after a coil of two loops is made from ...
A coil of one loop is made from a wire of length L and there after a coil of two loops is made from same wire, then the ratio of magnetic field at the centre of coils will be
A. 1:4
B. 1:1
C. 1:8
D. 4:1
Solution
Place the values in the formula for length of wire by taking two different radii into consideration and on equating them we find the answer.
A magnetic field is a vector field that describes the magnetic influence on an electric charge of other moving charges or magnetised materials.
Complete step by step solution:
Write all the values which are provided,
Length of the wire is L
Now we can let the radius of first and second loop be R1 and R2 respectively,
Then,
According to the question,
L=2πR1(for the first loop)
And,
L=2×2πR2(second loop)
Now equating we get,
2πR1=2×2πR2
Bringing R1and R2in one side we get,
R1R2=2×2π2π
By further solving we get,
R1R2=21
Now we know that magnetic field at the centre of the coil of radius R is given by,
B=2Rμ0nI
Now for the first and second loop the magnetic field at the centre of the coil of radius R1and R2is
B1=2R1μ0n1I
And,
B2=2R2μ0n2I
Now,
B2B1=2R2μ0n2I2R1μ0n1I
Now cancelling out μ0, 2 and I we get,
B2B1=n2R1n1R2
Now we know the values of n1=1, n2=2 and R1R2=21
Putting the values in the above equation we get,
B2B1=21×21
Which is equal to
B2B1=41
It can be also written as,
B1:B2=1:4
Therefore, the correct option is A.
Note: Students must remember that the radius of the two will not be same that is why we have two different radii i.e. R1 and R2.