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Question: A coil of mean area 500 cm2 and having 1000 turns is held perpendicular to a uniform field of 0.4 ga...

A coil of mean area 500 cm2 and having 1000 turns is held perpendicular to a uniform field of 0.4 gauss. The coil is turned through 180° in 110\frac{1}{10} second. The average include emf is

A

0.02 V

B

0.04 V

C

1.4 V

D

0.08 V

Answer

0.04 V

Explanation

Solution

Here, A=500cm2=500×104m2A = 500cm^{2} = 500 \times 10^{- 4}m^{2}

N=1000,B=0.4G=0.4×104TN = 1000,B = 0.4G = 0.4 \times 10^{- 4}T

t=110st = \frac{1}{10}s

When the coil is held perpendicular to the field the normal to the plane of the coil makes an angel of 00{^\circ} with the field B.

\therefore initial flux, φ1=BAcos0º=BA\varphi_{1} = BA\cos 0º = BA

Final flux φ2=BAcos0º=BA\varphi_{2} = BA\cos 0º = - BA

Average induced emf,

ε=N(φ2φ1t)=N(BABAt)\varepsilon = - N\left( \frac{\varphi_{2} - \varphi_{1}}{t} \right) = - N\left( \frac{- BA - BA}{t} \right)

=2NBAt=2×1000×0.4×104×500×1041/10= \frac{2NBA}{t} = \frac{2 \times 1000 \times 0.4 \times 10^{- 4} \times 500 \times 10^{- 4}}{1/10}

0.04V0.04V