Solveeit Logo

Question

Physics Question on Power

A coil of inductive reactance 31Ω31\, \Omega has a resistance of 8 Ω\Omega. It is placed in series with a condenser of capacitative reactance 25Ω25 \,\Omega. The combination is connected to an a.c. source of 110 V. The power factor of the circuit is :-

A

0.33

B

0.56

C

0.64

D

0.8

Answer

0.8

Explanation

Solution

Power factor =cosϕ=RZ=882+(3125)2=\cos \,\phi=\frac{ R }{| Z |}=\frac{8}{\sqrt{8^{2}+(31-25)^{2}}}
=882+62=810=0.8=\frac{8}{\sqrt{8^{2}+6^{2}}}=\frac{8}{10}=0.8