Question
Physics Question on Alternating current
A coil of inductance 300 mH and resistance 2 Ω is connected to a source of voltage 2 V. The current reaches half of its steady state value in
A
0.15 s
B
0.3 s
C
0.05 s
D
0.1 s
Answer
0.1 s
Explanation
Solution
The charging of inductance is given by
I=I0[1−e−Rt/L]
∴2I0=I0[1−e−RT/L]
or e−Rt/L=21 or LRt= 1n 2
or t=20.693×300×10−3
= 0.1 s