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Question: A coil of area 80 square cm and 50 turns is rotating with 2000 revolutions per minute about an axis ...

A coil of area 80 square cm and 50 turns is rotating with 2000 revolutions per minute about an axis perpendicular to a magnetic field of 0.05 Tesla. The maximum value of the e.m.f. developed in it is

A

200πvolt200\pi volt

B

10π3volt\frac{10\pi}{3}volt

C

4π3volt\frac{4\pi}{3}volt

D

23\frac{2}{3}volt

Answer

4π3volt\frac{4\pi}{3}volt

Explanation

Solution

e=NBAω;6muω=2πf=2π×200060e = NBA\omega;\mspace{6mu}\omega = 2\pi f = 2\pi \times \frac{2000}{60}

6mue=50×0.05×80×104×2π×200060=4π3\therefore\mspace{6mu} e = 50 \times 0.05 \times 80 \times 10^{- 4} \times 2\pi \times \frac{2000}{60} = \frac{4\pi}{3}