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Question

Physics Question on Magnetic Force

A coil of area 5 cm25 \, cm^2 having 2020 turns is placed in a uniform magnetic field of 10310^3 gauss. The normal to the plane of coil makes an angle 30∘30^{\circ} with the magnetic field. The flux through the coil is

A

6.67 ×10−4wb6.67 \, \times 10^{-4} wb

B

3.2 ×10−5wb3.2 \, \times 10^{-5} wb

C

5.9 ×10−4wb5.9 \, \times 10^{-4} wb

D

8.65 ×10−4wb8.65 \, \times 10^{-4} wb

Answer

6.67 ×10−4wb6.67 \, \times 10^{-4} wb

Explanation

Solution

Given that:
N = 20
B=103B = 10^3 gauss
=103×104 T=0.1T= 10^3 \times 10^4 \, T = 0.1T
A=5 cm2=5×10−4m2A = 5 \, cm^2 = 5 \times 10^{-4} m^2
θ=80∘\theta = 80^{\circ}
∴\therefore Flux through the coil
ϕ=NBA cos⁡ θ\phi = NBA \, \cos \, \theta
=20×0.1×5×10−4×cos⁡ 30∘= 20 \times 0.1 \times 5 \times 10^{-4} \times \cos \, 30^{\circ}
=10×10−4×32= 10 \times 10^{-4} \times \frac{\sqrt{3}}{2}
=53×10−4= 5 \sqrt{3} \times 10^{-4}
=865×10−4Wb= 865 \times 10^{-4} Wb