Question

A coil of 200Ω resistance and 1.0 H inductance is connected to an ac source of frequency $200 ⥂ / ⥂ 2\pi Hz.$ Phase angle between potential and current will be

• A. 30^o
• B. 90^o
• C. 45^o
• D. 0^o

Answer 1

Answer: (C)

45^o

Answer 2

$\tan\varphi = \frac{X_{L}}{R} = \frac{2\pi\nu L}{R} = \frac{2\pi \times \frac{200}{2\pi} \times 1}{200} = 1 \Rightarrow \varphi = 45^{o}$