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Question

Physics Question on Electromagnetic induction

A coil having 500 square loops of side 10 cm is placed normal to magnetic field which increases at a rate of 1 T s1^{-1}. The induced e.m.f. is

A

0.1 V

B

0.5 V

C

1 V

D

5 V

Answer

5 V

Explanation

Solution

Here, area A=500(10/100)2=5m2A = 500 (10/100)^2 = 5\, m^2
dBdt=1Ts1{ \frac{dB}{dt} = 1 \, T \, s^{-1}}
Induced e.m.f e=dϕdt=AdBdt=5×1\left|e\right| =\frac{d\phi}{dt} =\frac{A dB}{dt} = 5\times 1 = 5 volt.