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Question

Physics Question on Alternating current

A coil has an inductance of 0.7 H and is joined in series with a resistance of 220Ω220\, \Omega. When an alternative emf of 220 V at 50 cps is applied to it, then the wattless component of the current in the circuit is

A

5 A

B

0.5 A

C

0.7 A

D

7 A

Answer

0.5 A

Explanation

Solution

tanϕ=XLR=ωLR=2π?50?0.7220=1tan \,\phi = \frac{X_{L}}{R} = \frac{\omega L}{R} = \frac{2\pi?50?0.7}{220} = 1 ϕ=45\Rightarrow\quad\phi = 45^{\circ} and Z=R2+XL2=2202+2202=2202ΩZ = \sqrt{R^{2} + X_{L}^{2}} = \sqrt{220^{2} + 220^{2}} = 220 \,\sqrt{2}\,\Omega Wattles component of current =Iυsinϕ= I_{\upsilon}\, sin\phi =EυZsin45=2202202×12=05A= \frac{E_{\upsilon}}{Z}sin\,45^{\circ } = \frac{220}{220\sqrt{2}} \times \frac{1}{\sqrt{2}} = 0\cdot5\,A